In the following, we investigate the synchronization between
S1 and
S2, and compare the behavior of synchronization in the Markovian regime and non-Markovian regime. We suppose that the initial state of the system is $\tfrac{1}{\sqrt{2}}(| 0\rangle +| 1\rangle )\otimes \tfrac{1}{\sqrt{2}}(| 0\rangle +| 1\rangle )$. Meanwhile, we assume that the environment ancillae are identical and in the same initial state
ρe = ∣0〉〈0∣. From the numerical calculation, we find that the time for the subsystems to get anti-synchronized is different for different parameter region. In the parameter region of small
λ and large Δ, even though the Pearson coefficient can eventually approaches −1 with a long enough evolution time, the expectation values of the local observables become extremely small. In other words, the system has reached its steady state before the transient synchronization appears. We argue that in this case even though the Pearson coefficient can arrive at −1 finally, there is no visibility for this anti-synchronization. So in this paper when the Pearson coefficient has not reached −1 before the expectation value of the local observable decays to 10
−4 of the initial value, we say that the two qubits can not be synchronized. It is worth emphasizing that the magnitude of this value makes no qualitative difference to the following results in this paper. In figure
2(a) we display the behavior of Pearson coefficient between
S1 and
S2 in terms of detune Δ and coupling strength between two qubits
λ in the Markovian regime (
γ = 0). Without lose of generality, we suppose that the coupling strength between the subsystems and the environment ancilla
J = 0.3
ω, and
ω1 =
ω. To avoid the situation of extremely small expectation values of local observables, the final collision times we choose
N = 5000. As expected, we obtain a typical Arnold tongue which is shown in figure
2(a). It can be seen that the two subsystems tend to anti-synchronize in most area of parameter region except for very small values of
λ and large values of Δ. Only when the coupling strength between
S1 and
S2 is strong enough to compensate the effect of detune, the anti-synchronization appears. When we increase
N a little, the blue region in figure
2(a) would increase slightly. While as
N increases further we find that although some region (especially the region with small
λ and large Δ) turns into blue, i.e.
C12 ∼ − 1, the expectation value of the local observables would be extremely small before that. In this case there is no visibility of the synchronization, and according to our argument we say that it can not get anti-synchronized. From numerical calculation we find that by considering the visibility of synchronization when
N > 5000, the result makes no qualitative difference from figure
2(a).