It is demonstrated that for the isospin I = 1/2 πN scattering amplitude, TI=1/2(s, t), $s={\left({m}_{N}^{2}-{m}_{\pi }^{2}\right)}^{2}/{m}_{N}^{2}$ and $s={m}_{N}^{2}+2{m}_{\pi }^{2}$ are two accumulation points of poles on the second sheet of complex s plane, and are hence accumulation of singularities of TI=1/2(s, t). For TI=3/2(s, t), $s={\left({m}_{N}^{2}-{m}_{\pi }^{2}\right)}^{2}/{m}_{N}^{2}$ is the accumulation point of poles on the second sheet of the complex s plane. The proof is valid up to all orders of chiral expansions.
Qu-Zhi Li, Han-Qing Zheng. Singularities and accumulation of singularities of πN scattering amplitudes[J]. Communications in Theoretical Physics, 2022, 74(11): 115203. DOI: 10.1088/1572-9494/ac8869
In a previous publication, it is pointed out that in the L2I,2J = S11 channel partial wave πN scattering amplitude, there exist two virtual poles. [1] One lies below but close to ${c}_{L}=\tfrac{{\left({m}_{N}^{2}-{m}_{\pi }^{2}\right)}^{2}}{{m}_{N}^{2}}$, and another lies above but close to ${c}_{R}\,={m}_{N}^{2}\,+2{m}_{\pi }^{2}$. Here [cL, cR] defines the cut of partial wave amplitude caused by the u channel nucleon exchange. [2] Meanwhile, it is found that the dispersion representation for the phase shift has to be modified, and the net effect of the new contributions from virtual poles and the additional cut is vanishingly small, leaving previous analyses on the S11 partial wave unchanged. In this note, we will extend our previous analysis to all partial waves L2I,2J. We find that the existence of virtual poles are quite universal, but different channels behave rather differently.
The on-shell T-matrix elements for elastic πN scatterings depend on three Mandelstam variables:
where τa is Pauli matrices, and χi (χf) corresponds to the isospin wave function of the initial (final) nucleon state. The amplitudes with isospins I = 1/2, 3/2 can be written as
where the superscripts (${s}^{{\prime} }$), (s) denote the spins of the Dirac spinors, and q(p) and ${q}^{{\prime} }({p}^{{\prime} })$ are the 4-momenta of initial and final pions (nucleons), respectively. Functions A and B are scalar functions of s and t. Helicity amplitudes can be obtained by substituting the nucleon spinors by helicity eigenstates in the centre of mass frame
The first and second subscripts of T refer to the helicity of the initial and final nucleon, respectively, and ‘ + , − ’ are shorthands for helicity + 1/2 and − 1/2, respectively; ${z}_{s}=\cos \theta $ with θ the scattering angle. Partial wave amplitudes for total angular momentum J can be written as
where dJ is the standard Wigner d-function. Substituting equation (6) into equation (7), then using the relation between the Wigner d-function and the Legendre polynomial
with ${s}_{R}={\left({m}_{N}+{m}_{\pi }\right)}^{2}$ and ${s}_{L}={\left({m}_{N}-{m}_{\pi }\right)}^{2}$. In fact, amplitudes ${T}_{\pm }^{I,J}$ stand for scattering states with orbital angular momentum l = J ∓ 1/2 and parity $P={\left(-1\right)}^{l-1}$, respectively. The partial wave S-matrix is defined by
The scalar function AI and BI may be calculated by chiral perturbation theory at low energies.4(In the region [sL, sR] chiral expansions are expected to work well.) Here, we present the results at the ${ \mathcal O }({p}^{1})$ level,
where F and g denote the pion decay constant and the axial vector coupling constant, respectively. Here we however only need to concern the $1/(u-{m}_{N}^{2})$ term, which coefficient is immune to any chiral corrections, and its sign determines the existence of the zeros (poles) of the S-matrix.
Substituting equation (17) into equation (9) and using the Neumann equation
in which the neglected terms ⋯ denote the parts regular at cL and cR (see discussions below), which receive chiral corrections. The definition of y(s) is
This term leads to the existence of three branch points at s = 0, cL, cR in function ${B}_{C,S}^{I,J}$, and then in parity eigenstate amplitudes ${T}_{\pm }^{I,J}$. Further, when s tends to cR, it is easy to find that
The sign of the infinity is independent of the angular momentum J. Things will be different, however, when s tends to cL. It turns out that ${T}_{\pm }^{1/2,J}$ tends to $\mp {\left(-1\right)}^{J+1/2}\infty $, and ${T}_{\pm }^{3/2,J}$ tends to $\pm {\left(-1\right)}^{J+1/2}\infty $. Taking the definition of S-matrix equation (15), and the fact that 2iρ(s) is negative at s = cR, cL, conclusions can be drawn that:5(The emergence of S matrix zeros due to kinematical reasons is known, and χPT amplitudes can be consistently embedded into a unitary S matrix element. See for example the discussion in [4].)
1.
(1) In the region s ∈ (cR, sR), the S-matrix ${S}_{\pm }^{1/2,J}(s)$ must contain a zero6(This argument has been actually used a long time ago in [5]. We thank one referee who brings our attention to this paper.), while ${S}_{\pm }^{3/2,J}(s)$ does not need to have.
2.
(2) In the region s ∈ (sL, cL), both ${S}_{+}^{1/2,J}(s)$ and ${S}_{-}^{3/2,J}(s)$ contain a zero for J = 1/2, 5/2, 9/2, ⋯ , while both ${S}_{-}^{1/2,J}(s)$ and ${S}_{+}^{3/2,J}(s)$ contain a zero for J = 3/2, 7/2, 11/2, ⋯ . Or in other words, for I = 1/2 (I = 3/2), there exists a virtual pole vL ∈ (sL, cL) in each partial wave amplitude with even (odd) angular momentum.
Taking a few examples, in S31 channel there is no virtual pole, while in p waves,
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P11 channel contains a virtual pole vR ∈ (cR, sR), as well as the nucleon bound state;
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P13 channel contains a virtual pole in vR ∈ (cR, sR);
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P33 channel contains a virtual pole in vL ∈ (sL, cL).
A modification of the dispersion representation for function f defined in [1] in each channel may be needed accordingly, similar to what has been discussed in S11 channel [1]. Conclusions are similar in all channels: the contribution from the virtual pole to the phase shift is always exactly canceled by the additional contribution from the dispersion integral in f, when vL = cL (vR = cR). Taking for example the case that there exists only one virtual pole vL on the left. In this situation,
where ${S}^{{v}_{L}}$ represents the ‘S matrix’ of the newly found virtual pole vL, while Si depicts all other known poles. 7(For more details about the production representation, one can refer to [6–8].) Such an Scut is real and negative when s ∈ (sL, cL),8(Sphy(sL) = +1 according to equation (15). This is because sL is the branch point caused by the u channel continuous absorptive singularities, T(sL) itself is regular. For resonances Si = +1, for bound state or virtual state Si = −1, when s = sL. Particularly SvL is negative when s ∈ (sL, vL) and positive when s ∈ (vL, cL).) so the ‘spectral function’ $f=\mathrm{ln}{S}^{\mathrm{cut}}/2{\rm{i}}\rho $ maintains a cut ∈ (sL, cL) and its contribution $\tfrac{s}{\pi }{\int }_{{s}_{L}}^{{c}_{L}}\tfrac{\mathrm{Im}[\mathrm{ln}{S}^{\mathrm{cut}}(s^{\prime} )/2{\rm{i}}\rho (s^{\prime} )]}{s^{\prime} (s^{\prime} -s)}{\rm{d}}s^{\prime} $ exactly cancels the contribution from the virtual pole when vL = cL. In another situation when there exists a virtual pole on the right, i.e. vR ∈ (cR, sR), the ‘spectral function’ f is defined the same as in [1]:9(Except P11 channel, where there exists a nucleon bound state, the contribution of the virtual state remains.)
where the function $\bar{\rho }(s)$ is the ‘deformed’ ρ(s) with its cut ∈ [sL, sR], while the cut of the latter is defined on ( −∞ , sL] ∪ [sR, + ∞ ). Further, function $\bar{f}(s)$ is identical to f(s) when s lies in the physical region. Now −Scut > 0 when s ∈ (sL, cL) and − Scut < 0 when s ∈ (cR, sR). So $\mathrm{ln}-{S}^{\mathrm{cut}}/2{\rm{i}}\rho (s)$ contains a cut (cR, sR), on which its imaginary part is canceled by that from the second term on the r. h. s. of equation (26). Hence $\bar{f}$ contains an additional cut (sL, cR) coming from $-\pi /2\bar{\rho }(s)$, and its contribution on (sL, cR) is exactly canceled by that of the virtual pole when vR = cR. As a consequence all calculations made in [9] remain correct with very high accuracy.
The following discussions are dedicated to determining the location of those zeros. Let us focus on I = 1/2 for the moment. The explicit expressions of S-matrix elements read
$\begin{eqnarray}{S}_{\pm }^{1/2,J}(s)={{ \mathcal A }}_{\pm }^{1/2,J}(s)+{{ \mathcal B }}_{\pm }^{1/2,J}(s)\mathrm{ln}\displaystyle \frac{s-{c}_{L}}{s-{c}_{R}},\end{eqnarray}$
where $W\equiv \sqrt{s}$ denotes the center-of-mass frame energy and ${E}_{N}=(s+{m}_{N}^{2}-{m}_{\pi }^{2})/2\sqrt{s}$ is the nucleon energy. It is worth stressing that the function ${{ \mathcal B }}_{\pm }^{1/2,J}(s)$ is immune of χPT corrections.
Let ${v}_{R\pm }^{J}\in ({c}_{R},{s}_{R})$ denotes the position of the zero of ${S}_{\pm }^{1/2,J}(s)$, which gives
$\begin{eqnarray}\begin{array}{l}{S}_{\pm }^{1/2,J}({v}_{R\pm }^{J})={{ \mathcal A }}_{\pm }^{1/2,J}({v}_{R\pm }^{J})\\ \quad +{{ \mathcal B }}_{\pm }^{1/2,J}({v}_{R\pm }^{J})\mathrm{ln}\displaystyle \frac{{v}_{R\pm }^{J}-{c}_{L}}{{v}_{R\pm }^{J}-{c}_{R}}=0.\end{array}\end{eqnarray}$
Suppose ${v}_{R\pm }^{J}$ approaches cR for sufficiently large J, as will be verified a short while later, the solution of equation (30) may be obtained by iteration method
$\begin{eqnarray}{v}_{R\pm }^{J}={c}_{R}+({c}_{R}-{c}_{L}){{\rm{e}}}^{{{ \mathcal A }}_{\pm }^{1/2,J}({c}_{R})/{{ \mathcal B }}_{\pm }^{1/2,J}({c}_{R})}.\end{eqnarray}$
Using equation (29) and the fact that Pl[y(cR)] = Pl(1) = 1, one finds that ${{ \mathcal B }}_{\pm }^{1/2,J}({c}_{R})$ is negative and independent of J. Further, when J tends to ∞ , ${{ \mathcal A }}_{\pm }^{1/2,J}({c}_{R})$ goes to infinity. To prove this, notice that the function Ol−1 defined in equation (22) behaves as (taking l = 2k + 1 for example)
Hence, according to equation (28), as J → ∞ , the leading contribution of ${{ \mathcal A }}_{\pm }^{1/2,J}({c}_{R})$ is10(The contribution from chiral corrections will not diverge, since the contribution itself is regular when s ∈ (sL, sR), and notice that ∣Pl(x)∣ < 1 when x ∈ [ −1, +1] for arbitrary l—which is proved using the Laplace formula of Legendre function.)
From above, one concludes that ${v}_{R\pm }^{J}$ gets closer and closer to cR as J increases, according to equation (31). Hence, cR is the accumulation point of poles on the second sheet. What we have discussed is actually an example of a general mathematical theorem: as the sequence is bounded, it must have an accumulation, i.e. it has one convergent subsequence. Similarly, analyses can be made on the situation in the line segment (sL, cL). One finds that both ${v}_{L+}^{1/2,J}$ and ${v}_{L-}^{1/2,J}$ approaches cL when J → ∞ . Therefore, following the steps of [10], we prove that s = cL, cR are two accumulations of singularities of T1/2(s, t), on the second sheet of the complex s-plane. However, the proof in [10] on the statement that s = 0 is an accumulation of singularities on the second sheet of s plane for ππ scattering amplitudes is fully non-perturbative. Our proof given here is valid for all orders of perturbation chiral expansions.
The analyses can also be applied to the isospin 3/2 case, and only the final results are presented here:
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when $J=\tfrac{4n+1}{2}$ (n = 1, 2, 3, ⋯ ), ${S}_{-}^{3/2,J}$ maintains a zero ${v}_{L-}^{3/2,J}\in ({s}_{L},{c}_{L});$
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when $J=\tfrac{4n-1}{2}$ (n = 1, 2, 3, ⋯ ), ${S}_{+}^{3/2,J}$ maintains a zero ${v}_{L+}^{3/2,J}\in ({c}_{R},{s}_{R})$.
One further proves that the accumulation of zeros at cL occurs and that s = cL is an accumulation of singularities of T3/2(s, t) on the second sheet of the s plane.
The authors would like to thank Wei-Nian Zhang at Sichuan University, and Wei-Da Zheng for helpful discussions. This work is supported in part by National Nature Science Foundations of China under contract numbers 11975028 and 10925522.
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