In this work, our initial state is the ground state of ${{\rm{H}}}_{2}^{+}$, which is 1s
σg. Its relative strengths of the transitions to the
σu(
m = 0) and
πu (
m = ±1) channels play a commanding role in the determination of the MF-PMDs and MF-PADs by arbitrarily polarized attosecond pulses [
39]. For a linearly polarized laser, when the molecular axis is neither parallel nor perpendicular to the polarization vector, it takes the same general form as that for an elliptically polarized laser. In the case of
Rc = 2, the dipole transition to the channel
πu (perpendicular geometry) is far stronger than that to the channel
σu (parallel geometry) with
σ(⊥) = 528.5 kb and
σ(∥) = 38.95 kb, respectively. While for the case of
Rc = 4, they are
σ(∥) = 413.9 kb and
σ(⊥) = 284.8 kb, respectively [
39]. Consequently, at
Rc = 2, when the alignment angle is 0° (parallel geometry), only the transition to
σu has a contribution to the final MF-PMD and MF-PAD. When the alignment angle is slightly shifted, even only by 4°, the contribution from the
πu channel becomes more significant than that from the
σu channel. If the alignment angle is 45°, the electric amplitudes are equal in
x- and
y-directions, but the cross section of transition to
πu is much stronger than that to
σu, thus the final photoelectron distribution is
πu dominant and close to the results of perpendicular geometry as shown in figure
3. In the case of
Rc = 4, however, the transition cross sections to
σu and
πu are comparable. Actually, the one to
σ(∥) is even about 50% stronger than that to
σ(⊥). In this case, as the alignment angle shifts to 4°, it does not introduce much perpendicular geometry distribution to the final distribution and therefore, both the MF-PAD and MF-PMD do not change significantly. At the 45° alignment angle, where the
x- and
y-components of the electric field are equal, the parallel geometry distribution has a greater contribution to the final MF-PAD and MF-PMD than the perpendicular geometry distribution does, which is observed in the bottom row of figure
4.