1. Introduction
2. Preliminaries
2.1. Majorization lattice theory
2.2. Resource theory of coherence: coherence vector as vectorial quantifier of coherence
(C1) Bottom on maximally coherent states: $\rho \,={U}_{\mathrm{IO}}\left|{\psi }_{d}^{\mathrm{mcs}}\right\rangle \left\langle {\psi }_{d}^{\mathrm{mcs}}\right|{U}_{\mathrm{IO}}^{\dagger }\Longleftrightarrow \nu (\rho )={{\bf{0}}}_{d}$. | |
(C2) Top on incoherent states: $\rho \in { \mathcal I }({{ \mathcal H }}_{d})\Longleftrightarrow \nu (\rho )={{\bf{1}}}_{d}$. | |
(C3) Monotonicity under arbitrary incoherent operations: &ngr;(ρ) ⪯̸ &ngr;(Λ(ρ)) for any incoherent operation Λ and any state ρ. | |
(C4) Monotonicity under selective incoherent operations: $\nu (\rho )\preceq {\sum }_{n\,=\,1}^{N}{p}_{n}\,\nu ({\sigma }_{n})$ for any state ρ and for any incoherent operation Λ with incoherent Kraus operators $\{{K}_{n}\}{}_{n=1}^{N}$, where ${p}_{n}=\mathrm{Tr}({{\rm{K}}}_{n}\rho {{\rm{K}}}_{n}^{\dagger })$ and ${\sigma }_{n}\,={K}_{n}\rho {K}_{n}^{\dagger }/{p}_{n}$. | |
(C5) Convexity for pure-state decompositions: $\nu \left({\sum }_{k=1}^{M}{q}_{k}\left|{\psi }_{k}\right\rangle \left\langle {\psi }_{k}\right|\right)\preceq {\sum }_{k\,=\,1}^{M}{q}_{k}\,\nu \left(\left|{\psi }_{k}\right\rangle \left\langle {\psi }_{k}\right|\right)$. |
2.3. Resource theory of purity: spectrum as vectorial quantifier of mixedness
3. Results
3.1. The bottom for coherence and mixedness cannot be reached simultaneously by any state
There is no $\rho \in { \mathcal S }({{ \mathcal H }}_{d})$ such that $\nu (\rho )=\lambda (\rho )={{\bf{0}}}_{d}$, for any $d\geqslant 2$.
Assume that there is a state $\rho \in { \mathcal S }({{ \mathcal H }}_{d})$ such that $\nu (\rho )={{\bf{0}}}_{d}=\lambda (\rho )$. By property (C1), ρ is a maximally coherent state, that is, $\rho ={U}_{\mathrm{IO}}\left|{\psi }_{d}^{\mathrm{mcs}}\right\rangle \left\langle {\psi }_{d}^{\mathrm{mcs}}\right|{U}_{\mathrm{IO}}^{\dagger }$, whereas by property M1, ρ is the maximally mixed state $\rho =\tfrac{1}{d}{{\mathbb{1}}}_{d}$. But this is not possible, since ${U}_{\mathrm{IO}}\left|{\psi }_{d}^{\mathrm{mcs}}\right\rangle \left\langle {\psi }_{d}^{\mathrm{mcs}}\right|{U}_{\mathrm{IO}}^{\dagger }\ne \tfrac{1}{d}{{\mathbb{1}}}_{d}$. Therefore, there is no $\rho \in { \mathcal S }({{ \mathcal H }}_{d})$ such that $\nu (\rho )={{\bf{0}}}_{d}=\lambda (\rho )$.
3.2. Coherence–mixedness complementarity from a tensor-product majorization relation
There is no sequence of quantum states $\{{\rho }_{n}\in { \mathcal S }({{ \mathcal H }}_{d})\}{}_{n\in {\mathbb{N}}}$ such that ${\nu }_{1}({\rho }_{n}){\lambda }_{1}({\rho }_{n})\longrightarrow 1/{d}^{2}$ as $n\longrightarrow \infty $.
Let us assume that there is a sequence $\{{\rho }_{n}\}{}_{n\in {\mathbb{N}}}$ such that ${\mathrm{lim}}_{n\to \infty }g({\rho }_{n})=1/{d}^{2}$, with $g:{ \mathcal S }({{ \mathcal H }}_{d})\to {\mathbb{R}}$ given by $g(\rho )={\nu }_{1}(\rho ){\lambda }_{1}(\rho )$. Since ${\nu }_{1}(\rho )$ and ${\lambda }_{1}(\rho )$ are continuous functions, g is continuous.
The set of density matrices ${ \mathcal S }({{ \mathcal H }}_{d})$ is compact and g is continuous, then its image $\mathrm{Img}$ is a compact subset of ${\mathbb{R}}$, in particular, it is closed.
The sequence $\{g({\rho }_{n})\}{}_{n\in {\mathbb{N}}}\subseteq \mathrm{Img}$ is convergent to $1/{d}^{2}$ in a closed set, then $1/{d}^{2}\in \mathrm{Img}$. Therefore, there is a ${\rho }^{* }$ such that $g({\rho }^{* })=1/{d}^{2}$.
If $g({\rho }^{* })={\nu }_{1}({\rho }^{* }){\lambda }_{1}({\rho }^{* })=1/{d}^{2}$, then all the components of the tensor-product vector $\nu ({\rho }^{* })\otimes \lambda ({\rho }^{* })$ are equal to $1/{d}^{2}$, and thus $\nu ({\rho }^{* })={{\bf{0}}}_{d}=\lambda ({\rho }^{* })$. But this is in contradiction with lemma
The bottom element ${{\bf{0}}}_{{d}^{2}}$ is strictly majorized by the infimum $\bigwedge {{ \mathcal U }}_{d}^{\otimes }$, that is, ${{\bf{0}}}_{{d}^{2}}\prec \bigwedge {{ \mathcal U }}_{d}^{\otimes }$.
Since ${{\bf{0}}}_{{d}^{2}}$ is the bottom element of ${{\rm{\Delta }}}_{{d}^{2}}^{\downarrow }$, then ${{\bf{0}}}_{{d}^{2}}\preceq \bigwedge {{ \mathcal U }}_{d}^{\otimes }$.
Let us assume that ${{\bf{0}}}_{{d}^{2}}=\bigwedge {{ \mathcal U }}_{d}^{\otimes }$. Then, the first component of $\bigwedge {{ \mathcal U }}_{d}^{\otimes }$ is equal to $1/{d}^{2}$.
From the definition of the infimum of the set ${{ \mathcal U }}_{d}^{\otimes }$, we have that ${(\bigwedge {{ \mathcal U }}_{d}^{\otimes })}_{1}=\inf \{{\nu }_{1}(\rho ){\lambda }_{1}(\rho ):\rho \in { \mathcal S }({{ \mathcal H }}_{d})\}$. Therefore $\inf \{{\nu }_{1}(\rho ){\lambda }_{1}(\rho ):\rho \in { \mathcal S }({{ \mathcal H }}_{d})\}=1/{d}^{2}$, which implies that there is a sequence $\{{\rho }_{n}\}{}_{n\in {\mathbb{N}}}$ such that ${\mathrm{lim}}_{n\to \infty }{\nu }_{1}({\rho }_{n}){\lambda }_{1}({\rho }_{n})=1/{d}^{2}$. But, due to lemma
3.3. Optimal lower bound for qubit systems: analytical result
For a qubit system, the infimum of the tensor product for coherence and spectrum vectors is
See appendix
Figure 1. The Lorenz curves of (a) λ(ρp), (b) &ngr;(ρp), and (c) &ngr;(ρp) ⨂ λ(ρp)) for 100 qubit maximally coherent mixed states are plotted. The values of p are taken equally spaced from the interval [0, 1] (the color map indicates p increasing for blue to red colors). For the sake of clarity, these Lorenz curves are highlighted (dashed lines) for a particular state. The Lorenz curves of the bottom and top elements are also depicted (light blue lines). In addition, the Lorenz curve of the infimum $\bigwedge {{ \mathcal U }}_{2}^{\otimes }=\left(1/2,\sqrt{2}/4,1/8,3/8-\sqrt{2}/4\right)$, which coincides with the one of $\bigwedge {{ \mathcal U }}_{3}^{\otimes \,\mathrm{mcms}}$, is depicted ((c) black line). |
3.4. Bounds for qutrit systems: numerical results
Figure 2. The Lorenz curves of (a) λ(ρ), (b) &ngr;(ρ), and (c) &ngr;(ρ) ⨂ λ(ρ) for N M qutrit states (randomly sorted as is indicated in the main text) are plotted (gray lines). For the sake of clarity, these Lorenz curves are highlighted (dashed lines) for a particular state. The Lorenz curves of the bottom and top elements are also depicted (light blue lines). The coherence–mixedness complementarity relation for qutrit systems can be seen from (c) where the Lorenz curve of the infimum $\bigwedge {{ \mathcal U }}_{3}^{\otimes \,\mathrm{rdm}}$ ≈ (0.3396, 0.3307, 0.1833, 0.0610, 0.0405, 0.0215, 0.0147, 0.0046, 0.0041) (black line) is above to the Lorenz curve of the bottom 09. |
Figure 3. The Lorenz curves of (a) λ(ρp), (b) &ngr;(ρp), and (c) &ngr;(ρp) ⨂ λ(ρp) for 100 qutrit maximally coherent mixed states are plotted. The values of p are taken equally spaced from the range [0, 1] (the color map indicates p increasing for blue to red colors). For the sake of clarity, these Lorenz curves are highlighted (dashed lines) for a particular state. The Lorenz curves of the bottom and top elements are also depicted (light blue lines). In addition, the Lorenz curve of the infimum $\bigwedge {{ \mathcal U }}_{3}^{\otimes \,\mathrm{mcms}}\approx (0.3333,0.3333,0.1747,0.0714,0.0428,0.0194,0.0166,0.0042,0.0042)$((c) black line) is depicted. For qutrit systems, it seems to be sufficient to consider the set of maximally coherent mixed states in order to estimate the infimum of $\bigwedge {{ \mathcal U }}_{3}^{\otimes }$. |
Figure 4. Plot of the points $\left(m,{\nu }_{1}({\rho }_{m}){\lambda }_{1}({\rho }_{m})\right)$ for all the qutrit states randomly generated, that is, ${\rho }_{m}\in {{ \mathcal S }}^{\mathrm{rdm}}({{ \mathcal H }}_{3})$. There are no points below the straight line &ngr;1(ρ)λ1(ρ) = 1/3. |
Let $\rho \in { \mathcal S }({{ \mathcal H }}_{d})$.
Then
3.5. From vectorial to scalar coherence–mixedness complementarity relations
Let $\rho \in { \mathcal S }({{ \mathcal H }}_{d})$ and let $f:{{\mathbb{R}}}^{d}\to {\mathbb{R}}$ be a symmetric, strictly concave and additive function such that ${\mathrm{argmax}}_{u\in {{\rm{\Delta }}}_{d}}f(u)={{\bf{0}}}_{d}$ and $f({{\bf{1}}}_{d})=0$. Then
Since f is symmetric and strictly concave, f is strictly Schur-concave and continuous [11]. Then, $f\left(\nu (\rho )\right)$ is a coherence monotone and $f\left(\lambda (\rho )\right)$ is a mixedness measure [5, 24].
Given a state $\rho \in { \mathcal S }({{ \mathcal H }}_{d})$, from the majorization relation (
There is no sequence $\{{\rho }_{n}\in { \mathcal S }({{ \mathcal H }}_{d})\}{}_{n\in {\mathbb{N}}}$ such that ${\mathrm{lim}}_{n\to \infty }\tfrac{f(\nu ({\rho }_{n}))}{f({{\bf{0}}}_{d})}+\tfrac{f(\lambda ({\rho }_{n}))}{f({{\bf{0}}}_{d})}=2$.
Let us assume that there is a sequence $\{{\rho }_{n}\in { \mathcal S }({{ \mathcal H }}_{d})\}{}_{n\in {\mathbb{N}}}$ such that ${\mathrm{lim}}_{n\to \infty }\tfrac{f(\nu ({\rho }_{n}))}{f({{\bf{0}}}_{d})}+\tfrac{f(\lambda ({\rho }_{n}))}{f({{\bf{0}}}_{d})}=2$. Then, ${\mathrm{lim}}_{n\to \infty }f(\nu ({\rho }_{n})\otimes \lambda ({\rho }_{n}))=2f({{\bf{0}}}_{d})=f({{\bf{0}}}_{d}^{2})$. Since $\{\nu ({\rho }_{n})\otimes \lambda ({\rho }_{n})\}{}_{n\in {\mathbb{N}}}\subseteq {{\mathbb{R}}}^{{d}^{2}}$ is a bounded sequence, then, due to Bolzano–Weierstrass theorem, there exists a convergent subsequence $\{\nu ({\rho }_{{n}_{j})}\otimes \lambda ({\rho }_{{n}_{j}})\}{}_{j\in {\mathbb{N}}}$, that is, ${\mathrm{lim}}_{j\to \infty }\nu ({\rho }_{{n}_{j}})\otimes \lambda ({\rho }_{{n}_{j}})=u\in {{\rm{\Delta }}}_{{d}^{2}}$. Since f is continuous, $f({\mathrm{lim}}_{j\to \infty }\nu ({\rho }_{{n}_{j}})\otimes \lambda ({\rho }_{{n}_{j}}))={\mathrm{lim}}_{j\to \infty }f(\nu ({\rho }_{{n}_{j}})\otimes \lambda ({\rho }_{{n}_{j}}))$. Then, $f(u)=f({{\bf{0}}}_{d}^{2})$. Since f is strictly Schur-concave, $u={{\bf{0}}}_{d}^{2}$. Thus, ${\mathrm{lim}}_{j\to \infty }\nu ({\rho }_{{n}_{j}})\otimes \lambda ({\rho }_{{n}_{j}})={{\bf{0}}}_{d}^{2}=(1/{d}^{2},\ldots ,1/{d}^{2})$. But this is in contradiction with lemma