How machine learning conquers the unitary limit

Bastian Kaspschak,Ulf-G Meißner

Figure 6. Components of the normal vector ${\boldsymbol{n}}$ of the unitary limit surface at ${{\boldsymbol{U}}}^{* }={\pi }^{2}/4\left(1,\ldots ,1\right)$. As a gradient of ${ \mathcal F }$, this vector points towards the strongest ascent of f, which explains why its components are negative.